Introfor

12345678910111213141516171819202122232425262728293031323334353637383940414243#include int max(int x, int y){ return (x>y)? x:y;} int matrixPath(int arr[][4], int i, int j, int *cnt) { if(i==0 && j==0) return arr[0][0]; else if(i==0){ // printf("(((%d,%d)))\n",i,j); return (arr[0][j]+ matrixPath(arr, 0, j-1, cnt)); } else if(j==0){ // printf("((%d,%d))\n",i,j); return (arr[i][0]+ matrixPath(arr, ..

123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101#include#include #define FALSE 0#define TRUE 1 int n = 10;int w[3][10] = {0}; int Weight(int k, int p) { if (p

The way most people learn to multiply large numbers looks something like this: 86 x 57 ------ 602 + 4300 ------ 4902If you know your multiplication facts, this "long multiplication" is quick and relatively simple. However, there are many other ways to multiply. One of these methods is often called the Russian peasant algorithm. You don't need multiplication facts to use the Russian peasant algor..