Who likes it

def likes(names):
    if len(names) == 0:
        return "no one likes this"
    elif len(names) == 1:
        return f'{names[0]} likes this'
    elif len(names) == 2:
        return f'{names[0]} and {names[1]} like this'
    elif len(names) == 3:
        return f'{names[0]}, {names[1]} and {names[2]} like this'
    else:
        num = len(names) - 2
        return f'{names[0]}, {names[1]} and {num} others like this'

names의 크기에 따라서 출력값이 변하는 것을 고려해 조건을 나눠 출력했다.

 

 

def likes(names):
    n = len(names)
    return {
        0: 'no one likes this',
        1: '{} likes this', 
        2: '{} and {} like this', 
        3: '{}, {} and {} like this', 
        4: '{}, {} and {others} others like this'
    }[min(4, n)].format(*names[:3], others=n-2)

다른 사람의 풀이인데 너무 잘 되어 있다. 이런 코드를 많이 봐야겠다..